Best calculations I can find presume the following....
1 AA = 2,800 mAh (max)
mAh remains the same if multiple batteries used in series
Formula is "Hours (H) = Ah / A"
So, 4 to 5 hours essentially means a drain not exceeding 0.65 amps.
If 2,800 is anywhere reliable, then I'm needing something in excess of 11,400 mAh capacity, correct? Granted, I don't know what loss occurs in dropping from 12v to 6v.
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You can disregard. The issue that was making me consider this option has resolved itself.